How much solar energy (kJ) would have to be transferred to a 154.0 foot length of asphalt highway that is?
How much solar energy (kJ) would have to be transferred to a 154.0 foot length of asphalt highway that is 43.0 feet wide and 21.7 centimeters deep in order to raise the temperature 1.00 oC ?
The average density of asphalt is 721 kg/m3
The specific heat of asphalt is 0.920 kJ/kg-oC
first, I found the volume, and then I found the mass. Then I used the equation q=(c)(m)(change in temp.) and got the answer as 4.96872 but it’s not the right answer…
help please?
okay, I got it now. thankss =]









Create a video blog…instantly.
Just as a guess, perhaps you calculated the volume incorrectly, or did the conversion to cubic meters incorrectly. The rest is pretty straightforward, just multiplying by the given numbers with no further unit conversions necessary.
But you must get the volume in cubic meters first. It’s a pretty large number, between 50,000 and 100,000 m^3 (assuming I calculated it correctly …)
Hope this helps a little.
Comment by genericman1998 — January 6, 2006 @ 3:06 am